-39x^2+76x-32=-32

Solution for -39x^2+76x-32=-32 equation:

-39x^2+76x-32=-32

We move all terms to the left:

-39x^2+76x-32-(-32)=0

We add all the numbers together, and all the variables

-39x^2+76x=0

a = -39; b = 76; c = 0;
Δ = b2-4ac
Δ = 762-4·(-39)·0
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-76}{2*-39}=\frac{-152}{-78}
=1+37/39
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+76}{2*-39}=\frac{0}{-78}
=0
$